Answer by Alexis Wilke for Use of 'auto func(int)' before deduction of 'auto'...
In your example, there is really no reason that you could not just move the implementation of the function before main():#include <iostream>using namespace std; // you should avoid this, tooauto...
View ArticleAnswer by Griwes for Use of 'auto func(int)' before deduction of 'auto' in C++14
This is [dcl.spec.auto/11]:If the type of an entity with an undeduced placeholder type is needed to determine the type of an expression, the program is ill-formed. Once a non-discarded return statement...
View ArticleAnswer by songyuanyao for Use of 'auto func(int)' before deduction of 'auto'...
When auto is used as the return type in a function declaration that does not use the trailing return type syntax, the keyword auto indicates that the return type will be deduced from the operand of its...
View ArticleAnswer by Bartek Banachewicz for Use of 'auto func(int)' before deduction of...
Clang has a much better error message for that one:main.cpp:8:16: error: function 'func' with deduced return type cannot be used before it is defined auto ret = func(5); ^I guess that's self-explanatory.
View ArticleUse of 'auto func(int)' before deduction of 'auto' in C++14
I have compiled following program in GCC using C++14. #include <iostream>using namespace std;auto func(int i);int main() { auto ret = func(5); return 0;}auto func(int i) { if (i == 1) return i;...
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